A point mass oscillates along the `x-`axis according to the law `x = x_(0)cos(omegat - pi//4)` if the acceleration of the particle is written as, a `= A cos(omegat + delta)`, then :

Options

A. `A = x_0, beta = - (pi)/(4)`
B. ` A= x_0 omega^2, beta = (pi)/(4)`
C. ` A = x_0 omega^2, beta = - (pi)/(4)`
D. `A = x_0 omega^2, beta = (3 pi )/(4)`

Answer

D