A pendulumd made of a uniform wire of cross sectional area (A) has time T.When an additionl mass (M) is added to its bob, the time period changes to `T_(M). If the Young's modulus of the material of the wire is (Y) then `1/Y` is equal to:

Options

A. `[1-((T_M)/(T ))^2] (A)/(Mg)`
B. `[1-((T)/(T_M ))^2] (A)/(Mg)`
C. `[((T_M)/(T))^2-1] (A)/(Mg)`
D. `[((T_M)/(T ))^2 - 1 ] (Mg)/( A)`

Answer

C