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Calculate the force required to increase the length of a steel wire of cross- sectional area `10^(-6)m^(2)` by 0.5% given: `Y_(("for steel"))=2xx10^(11)N-m^(2)`

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`l/Lxx100=0.5%`
`impliesl/L=5xx10^(-3)`
So `F=YA l/L=2xx10^(11)xx10^(-6)xx5xx10^(-3)`
`=10^(3)N`
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MOTION-ELASTICITY-EXERCISE -3
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