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Young modulus of elasticity of steel is ...

Young modulus of elasticity of steel is `2xx10^(11)N//m^(2)`. If interatomic distance for steel is `3.2Å`, then, find the interatomic force constant.

Text Solution

Verified by Experts

`k=Yxxr_(0)=2xx10^(11)xx3.2xx10^(-10)=64Nm^(-1)`
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Knowledge Check

  • Young's modulus for steel is 2xx10^(10)N//m^(2) . If the interatomic distance for steel is 3 Å, then the interatomic force constant for steel will be

    A
    `6xx10^(-10)N//m`
    B
    `6N//m`
    C
    `6xx10^(-8)N//m`
    D
    `60N//m`

  • The Young's modulus of steel is 2xx10^(11)N//m^(2) . If the interatomic spacing of the metal is 2.5 Å. Then the interatomic force constant is,

    A
    40 N/m
    B
    35 N/m
    C
    25 N/m
    D
    50 N/m

  • If Young's modulus of iron is 2xx10''" N/m"^(2) and the interatomic spacing between two molecules is 3xx10^(-10) m the interatomic force constant is

    A
    60 N/m
    B
    120 N/m
    C
    30 N/m
    D
    180 N/m

    • Similar Questions

    Explore conceptually related problems

    Young 's modulus of steel is 2.0 xx 10^(11)N m//(2) . Express it is "dyne"/cm^(2) .

    Young's modulus of steel is 19xx10^(10) N//m^(2) Express it in "dyne"//cm^(2) . Here dyne is the CG unit of force.

    If young's modulus of iron be 2xx10^(11) Nm^(-2) and interatomic distance be 3xx10^(-10) m^(-2) , the intertomic force constant will be (in N//m )

    The bulk of modulus of a metal is 10^(10)(N)/(m^2) and Poisson's ratio 0.20 . If average distance between the molecules is 3Å the the interatomic force constant is

    A structural steel rod has a radius r(=10 mm) and a length l(=1 m). When a force F(= 100 kN) is applied, it stretches it along its length. Young's modulus of elasticity of the structural steel is 2.0xx10^(11) Nm^(-2) . What is the elastic energy density of the steel rod ?

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