Students in a physics class are studying how the angle at which a projectile is launched on level ground affects the projectile's hang time and horizontal range. Hang time can be calculated using the formula `t=(2v.sin(theta))/g`, where t is the hang time in seconds, v is the initial launch velocity, `theta` is the projectile angle with respect to level ground, and g is the acceleration due to gravity, defined as `9.8m//s^2`. Horizontal range can be calculated using the formula `R=(v^2sin(2theta))/g`, where R is the distance the projectile travels from the launch site, in feet. Which of the following gives the value on v, in terms of R, t and `theta`?

Options

A. `v=(tsin(theta))/(2Rsin(theta))`
B. `v=(2tsin(theta))/(Rsin(theta))`
C. `v=(2Rsin(theta))/(t sin(2theta))`
D. `v=(2Rsin(2theta))/(t sin(theta))`

Answer

C