A circle of radius `5u n i t s` touches the coordinate axes in the first quadrant. If het circle makes one complete roll on x-a xi s along he positive direction of x-a xi s , find its equation in new position.

Explanation

Here `(5,5)` is the center of circle which is touching both the coordinate axes in first quadrant and 5 is the radius of circle, then `(x-5)^{2}+(y-5)^{2}=5^{2}`. is the equation of the circle


Now it makes one complete roll along positive `{X}` axis, hence its `{x}` coordinate of center will change its position to `5+10 pi` while y coordinate will remain the same.


`therefore` The final equation will be, `(x-(5+10 pi))^{2}+(y-5)^{2}=5^{2}`.