In the parallelogram ABCD , AB = 2AD . Prove that the bisectors of the angles `angleBAD and angleABC` meet at the mid-point of DC at right -angles.

In the parallelogram ABCD , AP and DP are the bisectors of the angleBAD and angleADC respectively. Find the angleAPD

In a parallelogram ABCD, the bisectors of the consecutive angles angleA and angleB intersect at P. Show that angleAPB=90^(@) .

If in the parallelogram ABCD angleA : angleB = 3 : 2 , then find the angles of the parallelogram ABCD.

ABCD is a cyclic quadrilateral .The side BC is extended to E .The bisectors of the angles angleBADandangleDCE intersect at the point P .Prove that angleADC=angleAPC .

Prove analytically that the bisectors of the interior angles of a triangle are concurrent.

In a parallelogram ABCD, angleDAB = 40^(@) find the other angles of the parallelogram.

ABCD is a cyclic quadrilateral. The side BC of it is extended to E . Prove that the two bisectors of angleBADandangleDCE meet on the circumferncee of the circle .

In the parallelogram ABCD , M is the mid-point of the diagonal BD, BM bisects equally angleABC then the measurement of angleAMB =