Find the equation of the circle whose centre is at `(3,-1)` and which cuts off a chord of length `6u n i t s` on the line `2x-5y+18=0.`

Explanation

To find the equation of the circle with center at (3, -1) that cuts off a chord of length 6 units on the line given by the equation \(2x - 5y + 18 = 0\), we can follow these steps:

### Step 1: Write the general equation of the circle
The general equation of a circle with center \((h, k)\) and radius \(r\) is given by:
\[ (x - h)^2 + (y - k)^2 = r^2 \]
Here, the center is \((3, -1)\), so we can write:
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