Find the equation of a circle whose diameters are `2x-3y+12a n dx+4y-5=0` and area is `154 `squareunits dot

Explanation

Equation of diameter given are `2x−3y=−12 `and `x+4y=5`

Let us solve these two equation to get the centre of the circle.

`2x−3y=−12.....(1)`

`x+4y=5(xx2)`

`2x+8y=10.....(2)`

Subtracting (1) from (2), we get

`⇒2x+8y−2x+3y=10−(−12)`

`⇒11y=22`

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