Find the equation of the circle which passes through the point of intersection of the lines `3x-2y-1=0a n d4x+y-27=0` and whose centre `(2,-3)` .

Explanation

To find the equation of the circle that passes through the point of intersection of the lines \(3x - 2y - 1 = 0\) and \(4x + y - 27 = 0\) and has its center at \((2, -3)\), we can follow these steps:

### Step 1: Find the point of intersection of the two lines
We have the equations:
1. \(3x - 2y - 1 = 0\)
2. \(4x + y - 27 = 0\)

To find the intersection, we can solve these equations simultaneously.
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