Find the circle and radius of the circle given by the equation `2x^2+2y^2+3x+4y+9/8=0.`

Explanation

In the given equation the coefficients of x2 and y2 are not unity. So, we re-write the equation to make the coefficients of `x^2` and `y^2` unity.


We have,` 2x^2+2y^2+3x+4y+9/8​=0`


`x^2+y^2+(3/2)x+2y+9/16​=0`


So, the coordinates of the centre are (−3/4,−1) and thus, radius =` sqrt((3/4​)^2+(1)^2−(9/16))​
​=1`