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Find the equation of the circle concentr...

Find the equation of the circle concentric with the circle `2x^2+2y^2-8x+10 y-39=0.`

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Given,`2x^2+2y^2-8x+10 y-39=0.`
=`x^2+y^2-4x+5y-39/2=0`
center is `(2,-5/2)`
Equation of circle is `(x-2)^2+(y+5/2)^2=a^2`
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RD SHARMA-THE CIRCLE-Solved Examples And Exercises
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