Find the equation of the hyperbola whose foci are `(6,4)a n d(-4,4)` and eccentricity is 2.

Explanation

Let `(h,k)` are the coordinates of the center of the hyperbola.

Then, equation of the hyperbola,

`(x-h)^2/a^2 - (y-k)^2/b^2 = 1`

Now, center of the hyperbola is the midpoint of the foci.

Here, foci are given `(6,4) and (-4,4).`

`:. h = (6-4)/2 = 1 and k = (4+4)/2 = 4`

So, the equation becomes,

`(x-1)^2/a^2 - (y-4)^2/b^2 = 1`

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