Referred to the principal axes as the axes of coordinates find the equation of the hyperbola whose foci are at `(0,+-sqrt(10))` and which passes through the point `(2,3)dot`

Explanation

Since, the foci of the given hyperbola are F′(0,−10
​) and F(0,10
​) which lie on the X-axis and mid-point of the segment F′F is (0,0).
Therefore origin is the centre of the hyperbola and its transverse axis lies along Y-axis, hence the equation of the hyperbola can be taken as

`(y^2)/(a^2)​−(x^2)/(b^2)=1 .........(i)`


As the foci are `(0,+-sqrt(10)
​)`

So, `ae=sqrt(10)`

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