Find the middle term in the expansion `(2/3x^2-3/(2x))^(20)` .

Explanation

To find the middle term in the expansion of \((\frac{2}{3}x^2 - \frac{3}{2x})^{20}\), we can follow these steps:

### Step 1: Identify the values of \(a\), \(b\), and \(n\)
In the expression \((\frac{2}{3}x^2 - \frac{3}{2x})^{20}\), we can identify:
- \(a = \frac{2}{3}x^2\)
- \(b = -\frac{3}{2x}\)
- \(n = 20\)

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