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If Delta(r)=|(r-1,n,6),((r-1)^(2),2n^(2)...

If `Delta_(r)=|(r-1,n,6),((r-1)^(2),2n^(2),4n-2),((r-1)^(3),3n^(3),3n^(2)-3n)|` then `sum_(r=1)^(n)Delta_(r)=`

A

0

B

`n^(2)`

C

`2^(n)`

D

`2^(n)-n^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
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