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|(a-b,b-c,c-a),(b-c,c-a,a-b),(c-a,a-b,b-...

`|(a-b,b-c,c-a),(b-c,c-a,a-b),(c-a,a-b,b-c)|=`

A

0

B

1

C

abc

D

`a+b+c`

Text Solution

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The correct Answer is:
A
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