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|(1+a,b,c),(a,1+b,c),(a,b,1+c)|=...

`|(1+a,b,c),(a,1+b,c),(a,b,1+c)|=`

A

0

B

1

C

`abc(1+a+b+c)`

D

`abc+ab+bc+ca`

Text Solution

Verified by Experts

The correct Answer is:
D
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