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Find tan 20^(@) + tan40^(@) + sqrt(3)tan...

Find `tan 20^(@) + tan40^(@) + sqrt(3)tan20^(@)tan40^(@)`.

A

`1`

B

`1//sqrt(3)`

C

`sqrt(3)`

D

`0`

Text Solution

Verified by Experts

The correct Answer is:
C
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A =(cos 9^(@) - sin 9^(@))/(cos 9^(@) + sin 9^(@)) , B = (cos 21^(@) + sin 21^(@))/(cos21^(@) -sin21^(@)) and C= tan 20^(@) + tan40^(@) + sqrt(3)tan20^(@) tan40^(@) then descending order is:

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Assertion (A): tan40^(@) + tan 80^(@) - sqrt(3)tan 40^(@) tan80^(@)=-sqrt(3) Reason ( R): tan( A + B) =tan A + tan B + tan(A + B) tan A tan B

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DIPTI PUBLICATION ( AP EAMET)-TRIGONOMETRIC RATIOS AND IDENTITIES -EXERCISE 1 B ( COMPOUNDS ANGLES )
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