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cos A cos 2A cos 4A .......cos^(2^(n-1))...

`cos A cos 2A cos 4A .......cos^(2^(n-1))A=`

A

`(sin 2^(n) A )/(2^(n) sin A ) `

B

`(2^(n) sin2^(n) A )/(sin A ) `

C

`(2^(n) sin A )/( sin 2^(n)A)`

D

`(sin A)/(2^(n) sin 2^(n) A) `

Text Solution

Verified by Experts

The correct Answer is:
A
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