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cos alpha + cos beta + cos gamma + cos (...

`cos alpha + cos beta + cos gamma + cos ( alpha + beta + gamma ) =`

A

`4 sin""((alpha + beta )/(2))* cos""((beta + gamma )/(2)) * cos ((gamma + alpha )/(2))`

B

`4 cos""((alpha + beta )/(2)) * cos""((beta + gamma )/(2)) * cos ""((gamma + alpha )/(2))`

C

`4 sin""((alpha + beta )/(2))* sin ((beta + gamma )/(2)) * sin""(( gamma + alpha )/(2))`

D

`4 cos ""((alpha + beta )/(2)) * cos""((beta + gamma )/(2))* sin""((gamma + alpha )/(2))`

Text Solution

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The correct Answer is:
B
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