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sin""(3 theta )/(2) cos""(theta )/(2) co...

`sin""(3 theta )/(2) cos""(theta )/(2) cos theta = `

A

`(1)/(4) [sin theta + sin 2 theta + sin 3 theta ]`

B

`(1)/(4)[sin theta - sin 2 theta + sin 3 theta ]`

C

`(1)/(4)[sin theta + sin 2 theta - sin 3 theta ]`

D

`(1)/(4)[sin theta - sin 2 theta - sin 3 theta ]`

Text Solution

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The correct Answer is:
A
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