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sin 70^@ - cos 40^(@) =...

`sin 70^@ - cos 40^(@) =`

A

`sin 10^(@) `

B

`cos 10^(@)`

C

`tan 10^(@) `

D

`cot 10^(@) `

Text Solution

Verified by Experts

The correct Answer is:
A
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sin 10^(@) + sin 20^(@) + sin 40^(@) + sin 50^(@) - sin 70^(@) - sin 80^(@) =

cos 40^(@) + cos 80^(@) + cos 160^(@) =

sin 20^(@) * sin 40^(@) * sin 60^@ * sin 80^(@) =

Prove that sin 50^(@) - sin 70^(@) +sin 10^(@) =0 .

sin 40^(@) - sin 80^(@)+ sin 160^(@) =

if ( cos ^(3) 20^@ + cos^(3) 40^(@))/( cos 20^@+ cos 40^(@)) = k ,then the value of k is

cos 20^(@) + cos 40^(@) + cos 60^(@) +...+cos160^(@)+cos 180^(@)=

cos 20^(@)* cos 40^(@) * cos 60^(@) * cos 80^(@) =

cos 70^(@) + sin 40^(@)=

cos 10^(@) cos 30^(@) cos 50^(@) cos 70^(@) =