If tan""((theta)/(2))=sqrt([(1-e)/(1+e)]...

If `tan""((theta)/(2))=sqrt([(1-e)/(1+e)]) tan""((alpha)/(2))` then ` cos alpha=`

`( cos theta - e)/(1-e cos theta )`

`( cos thea + e )/( 1-e cos theta ) `

`( cos theta - e)/(1+ e cos theta ) `

`( cos theta + e)/(1+e cos theta ) `

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(cos x )/( cos (x-2y))= lambda implies tan(x-y) tan y=
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