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If `cos alpha + cos beta = a, sin alpha + sin beta = b and theta` is the arithmetic mean between `alpha and beta ` then ` sin 2 theta + cos 2 theta ` is equal to

A

`(a+b)^(2)//(a^(2)+b^(2))`

B

`(a-b)^(2)//(a^(2)+b^(2))`

C

`(a^(2)-b^(2))//(a^(2)+b^(2))`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
D
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