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DIPTI PUBLICATION ( AP EAMET)-INVERSE TRIGONOMETRIC FUNCTIONS-EXERCISE 1
- tan(1/2Cos^(-1)0)=
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- tan[1/2Cos^(-1)(sqrt5/3)]=
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- cot(pi/4-2Cot^(-1)3)=
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- sin[pi/3+Cos^(-1)(-1/2)]=
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- sin{"Sin"^(-1)1/2+"Cos"^(-1)1/2}=
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- sec^(2)(Tan^(-1)2)+cosec^(2)(Cot^(-1)3)=
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- tan("Tan"^(-1)1/2+"Tan"^(-1)1/3)=
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- cos("Sin"^(-1)3/5+"Sin"^(-1)5/13)=
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- Find the value of tan(Cos^(-1)4/5 + Tan^(-1) 2/3)
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- Sin^(-1)(3/5)+Sin^(-1)(8/17)=
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- Cos^(-1)(3/5)+Cos^(-1)(12/13)=
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- Sin^(-1)(4/5)-Sin^(-1)(5/13)=
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- Cot^(-1)(4/3)-Cot^(-1)(15/8)=
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- Cos^(-1)(5/13)+Cos^(-1)(3/5)=Cos^(-1)xrArrx=
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- Sin^(-1)(24/25)+Tan^(-1)(5/12)=
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- Sin^(-1)(3/5)-Cos^(-1)(12/13)=
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- Sin^(-1)(3/5)+Cos^(-1)(5/sqrt34)=
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- cos[Cos^(-1)(-1/7)+Sin^(-1)(-1/7)]=
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- Sin^(-1)((-sqrt2)/2)+Cos^(-1)(-1/2)-Tan^(-1)(-sqrt3)-Cot^(-1)(1/sqrt3)...
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- Cos^(-1)((-1)/2)-2Sin^(-1)(1/2)+3Cos^(-1)((-1)/sqrt2)-4Tan^(-1)(-1)=
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