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DIPTI PUBLICATION ( AP EAMET)-INVERSE TRIGONOMETRIC FUNCTIONS-EXERCISE 1
- "Tan"^(-1)1/2+"Tan"^(-1)1/3=
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- "Tan"^(-1)3/2-"Tan"^(-1)1/5=
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- "Sec"^(-1)sqrt34/5+Cosec^(-1)sqrt17=
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- The value of cot("Cosec"^(-1)5/3+"Tan"^(-1)2/3) is
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- 2"Tan"^(-1)1/3+"Tan"^(-1)1/7=
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- 4tan^(-1)(1/5)-tan^(-1)(1/239)=
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- Prove that sin^(-1)((4)/(5))+2 Tan^(-1)((1)/(3)) = (pi)/2.
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- Sin^(-1)(16/65)+2Tan^(-1)(1/5)=
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- Cos^(-1)(63/65)+2Tan^(-1)(1/5)=
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- "Tan"^(-1)5/6+1/2"Tan"^(-1)11/60=
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- 2"Tan"^(-1)1/5+"Tan"^(-1)1/7+2"Tan"^(-1)1/8=
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- 4"Tan"^(-1)1/5-"Tan"^(-1)1/70+"Tan"^(-1)1/99=
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- "Tan"^(-1)1/3+"Tan"^(-1)1/5+"Tan"^(-1)1/7+"Tan"^(-1)1/8=
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- The value of cot[Cot^(-1)7+Cot^(-1)8+Cot^(-1)(18)] is
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- Sin^(-1)(xsqrt(1-y^(2))+ysqrt(1-x^(2)))=
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- Cos^(-1)(xy-sqrt(1-x^(2))sqrt(1-y^(2)))=
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- Tan^(-1)((3x-x^(3))/(1-3x^(2)))=
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- tan[2Tan^(-1)((sqrt(1+x^(2))-1)/x)]=
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- tan(Cos^(-1)x)=
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- sin(Cot^(-1)(cos(Tan^(-1)x)))=
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