2"Tan"^(-1)1/5+"Tan"^(-1)1/7+2"Tan"^(-1)...

`2"Tan"^(-1)1/5+"Tan"^(-1)1/7+2"Tan"^(-1)1/8=`

`pi`

`pi//2`

`pi//4`

`3pi//4`

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The correct Answer is:

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4"Tan"^(-1)1/5-"Tan"^(-1)1/70+"Tan"^(-1)1/99=
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"Tan"^(-1)1/3+"Tan"^(-1)1/5+"Tan"^(-1)1/7+"Tan"^(-1)1/8=
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Sin^(-1)(xsqrt(1-y^(2))+ysqrt(1-x^(2)))=
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tan[2Tan^(-1)((sqrt(1+x^(2))-1)/x)]=
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tan(Cos^(-1)x)=
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sin(Cot^(-1)(cos(Tan^(-1)x)))=
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Prove that cos[Tan^(-1){sin(Cot^(-1)x)}] = sqrt((x^(2)+1)/(x^(2)+2))
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2Tan^(-1)(cosx)=
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tan(2Tan^(-1)(sinx))=
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Tan^(-1)(cotx)-Tan^(-1)(cot2x)=
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2Tan^(-1)((sqrt(a-b))/(a+b)"tan"x/2)=
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tan[1/2"Sin"^(-1)(2a)/(1+a^(2))+1/2"Cos"^(-1)(1-a^(2))/(1+a^(2))]=
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tan[1/2Sin^(-1)((2x)/(1+x^(2)))-1/2Cos^(-1)((1-y^(2))/(1+y^(2)))]=
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Prove that sin[Cot^(-1) (2x)/(1-x^2)+Cos^(-1)((1-x^(2))/(1+x^(2)))]=1.
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