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DIPTI PUBLICATION ( AP EAMET)-LIMITS AND CONTINUITY-Exercise 1C(Continuity)
- The function f(x)=x+[x]" at "x=1//2" is "
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- The function f(x)=x+[x]" at "x=1//2" is "
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- The function f(x)=x-[x]" when x=2 is "
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- The function f(x)=(1+x)^(5//x), f(0)=e^(5)" at x =0 is "
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- The function f(x)=(x tan 2x)/(sin 3x sin 5x)" for "x ne 0, f(0)=2//17"...
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- The function f(x)=(cos 3x-cos 4x)/(x sin 2x)"for "x ne 0, f(0)=7//4"at...
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- The function f(x)=(1-cos x)/(x^(2))" for "x ne 0, f(0)=1" at x=0 is"
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- The function f(x)=(3sin x-sin 3x)/(x^(3))" for "x ne 0, f(0) =1 at x=0...
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- The function f(x)=(1-cos ax)/(1-cos bx)"for "x ne 0, f(0)=a/b" at x= 0...
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- The function f(x)=(sqrt(1+x^(2))-sqrt(1-x^(2))/(x^(2))"for "x ne 0, f(...
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- The function f(x) =(sqrt(x^(2)+3)-2)/(x-1)"for "x ne 1, f(1)=1//2" at ...
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- The function f(x) =(7|x|+5x)/(7|x|-5x) for x ne 0, f(0)=6" at x =0 is ...
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- If f(x)=1/(3^(1//x)+1)," then at x=0, f(x) is"
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- The function f(x) =[(x-1)/(1+e^(1/(x-1))]]" for "x ne 1, f(1)=0" ...
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- The function f(x) =(e^(1//x^(2))/(e^(1//x^(2))-1)" for "x ne 0,f(0)=1"...
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- f(x) = (x - [x]) sin ((1)/(X)) , at x = 0 , f is
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- If f(x)=x sin ""1/x"for "x ne 0, f(0)=0" then at x"=0, f(x) is
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- If f(x)=x cos""1/x^(2)" for "x ne 0, f(0)=1" then at x=0, f(x) is"
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- If f(x)=(x)/(1+e^(1//x))"for "x ne 0, f(0)=0" then at x=0, f(x) is"
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- The function f(x) =(xe^(1//x))/(1+e^(1//x))+sin""1/x" for "x ne 0, f(0...
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