Home
Class 12
MATHS
If 0 lt x lt 1, the first negative term ...

If `0 lt x lt 1`, the first negative term in the expansion of `(1+x)^(27//5)` is

A

`5^(th)` term

B

`6^(th)` term

C

`7^(th)` term

D

`8^(th)` term

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • BINOMIAL THEOREM

    DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 1A (BINOMIAL THEOREM WITH INTEGRAL INDEX)|149 Videos

  • BINOMIAL THEOREM

    DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 1B (BINOMIAL COEFFICIENTS)|83 Videos

  • APPLICATIONS OF DIFFERENTIATION

    DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 2 SET-4 (SPECIAL TYPE QUESTIONS)|15 Videos

  • CIRCLE

    DIPTI PUBLICATION ( AP EAMET)|Exercise Set 4|4 Videos

Similar Questions

Explore conceptually related problems

The first negative term in the expansion of (1+x)^(3//4) is

If x > 0 , write the first negative term in the expansion of (1 + 2x)^(23//2)

For x = 5/7 , If t_k is the first negative term in the expansion of (1+x)^(7//5) , then t_1, + t_2, + …..t_k =

If T_(r +1) is the first negative term in the expansion of (1+x)^(7//2) then r =

For |x| lt 1 , the constant term in the expansion of (1)/((x-1)^(2)(x-2) is :