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Larger of 99^50+100^50 and 101^50...

Larger of `99^50+100^50 and 101^50`

A

`99^50+100^50`

B

`101^50`

C

can not be determined

D

none

Text Solution

Verified by Experts

The correct Answer is:
B
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DIPTI PUBLICATION ( AP EAMET)-BINOMIAL THEOREM-EXERCISE 1A (BINOMIAL THEOREM WITH INTEGRAL INDEX)
  1. If (1)/(sqrt(4x+1)){(1+(sqrt(4x+1))/(2))^n-(1-(sqrt(4x+1))/(2))^n}=a0+...

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  2. (sqrt2+1)^6+(sqrt2-1)^6=

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  3. Larger of 99^50+100^50 and 101^50

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  4. Larger of 199^100+200^100 and 201^100 is

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  5. 11^9+9^11 is divided by

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  6. If n is a positive integer then 11^n-10n-1 is divided by

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  7. If n is a positive integer then 49^n + 16n-1 is divided by

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  8. The remainder when 2^2000 is divided by 17 is

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  9. The remainder left out when8^(2n)-(62)^(2n+1) is divided by 9 is

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  10. If (3+sqrt8)^n - I+F where In are positive integer , 0 lt F lt 1 then ...

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  11. If (4+sqrt15)^n=I+F when I, n are positive integers, 0 lt F lt 1 then ...

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  12. If (7+4sqrt3)^n=I+F where I and n are +ve integers and F is +ve proper...

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  13. Let R=(5 sqrt5+11)^(2n+1) , f=R-[R]. Then Rf=

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  14. If (6 sqrt6+14)^(2n+1)=R and F=[R], where [R] denotes the greatest int...

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  15. If R=(5 +sqrt21)^(2n+1) and f=R-[R], where [R] denotes the greatest in...

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  16. Let R=(2+sqrt3)^(2n) and f=R-[R] where [ ] denotes the greatest intege...

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  17. For natural numbers m, n if (1-y)^m (1+y)^n=1+a1 y +a2 y^2 + …, and a1...

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  18. The middle term in the expansion of (x+(1)/(x))^10 is

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  19. The middle term of (a//x-x//a)^10 is

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  20. Middle term in the expansion of (2x-(3)/(x))^15 is

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