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If the circles x^(2)+y^(2)+4x-2y-220=0, ...

If the circles `x^(2)+y^(2)+4x-2y-220=0, x^(2)+y^(2)-4x+4y-92=0` touch each other then the points of contact is

A

(-2,1)

B

(2,-2)

C

(10,-8)

D

(0,-1)

Text Solution

Verified by Experts

The correct Answer is:
C
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