Home
Class 12
MATHS
If the tangents at (5,12) and (12,-5) to...

If the tangents at (5,12) and (12,-5) to a circle are perpendicular to each other then the radius of the circle is

A

12

B

5

C

13

D

none

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • CIRCLE

    DIPTI PUBLICATION ( AP EAMET)|Exercise Exercise 1C(Pole, Polar)|107 Videos
  • CIRCLE

    DIPTI PUBLICATION ( AP EAMET)|Exercise Exercise 1D(Angle Between Circles)|49 Videos
  • CIRCLE

    DIPTI PUBLICATION ( AP EAMET)|Exercise Exercise 1A(Circle)|110 Videos
  • BINOMIAL THEOREM

    DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 2 (SPECIAL TYPE QUESTIONS) SET - 4|4 Videos
  • COMPLEX NUMBERS

    DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 2 (SPECIAL TYPE QUESTIONS) (SET - 4)|5 Videos

Similar Questions

Explore conceptually related problems

The tangents at (5,12) and (12,-5) to the circle x^(2)+y^(2)=169 are

The tangent at any point of a circle is perpendicular to the radius through the point of contact.

From a point P, the length of the tangent to a circle is 12 cm, and the distance of P from the centre is 13 cm. The radius of the circle is

How can you prove the converse of the above theorem. "If a line in the plane of a circle is perpendicular to the radius at its end point on the circle , then the line is tangent to the circle " .

Choose the correct answer and give justification for each. From a point Q, the length of the tangent to a circle is 4 cm. and the distance of Q from the centre is 5 cm. The radius of the circle is

If 5x - 12y + 10 = 0 and 12y - 5x + 16 = 0 are two tangents to a circle, then the radius of the circle is

Circle touching both the axes and radius 5 is

From a point Q , the length of the tangent to a circle is 24 cm . And the distacne Q from the centre is 25cm . The radius of the circle is

If the rate of change in the radius of a circle is 0.02 cm/sec, then the rate of change in the area of the circle when the radius is 5 cm is

DIPTI PUBLICATION ( AP EAMET)-CIRCLE-Exercise 1B(Circle-Line)
  1. If a tangnet drawn from the point (4,0) to the circle x^(2)+y^(2)=8 to...

    Text Solution

    |

  2. The tangent at (3,4), (4,-3) to the circle x^(2)+y^(2)=25" are"

    Text Solution

    |

  3. If the tangents at (5,12) and (12,-5) to a circle are perpendicular to...

    Text Solution

    |

  4. The locus of the point of intersection of two perpendicular tangents t...

    Text Solution

    |

  5. The locus of the point of intersection of the perpendicular tangents t...

    Text Solution

    |

  6. The locus of the point of intersection of the perpendicular tangents t...

    Text Solution

    |

  7. If the tangent from a point P to the circle x^(2)+y^(2)=1 is perpendic...

    Text Solution

    |

  8. The locus of the point of intersection of two tangents drawn to the ci...

    Text Solution

    |

  9. The locus of the feet of the perpendicular drawn from the point (a,0) ...

    Text Solution

    |

  10. The locus of the middle points of portions of the tangents to the circ...

    Text Solution

    |

  11. If 4t^(2)-5m(2)+6l+1=0, then the line lx+my+1=0 touches the circle

    Text Solution

    |

  12. The locus of the point (l,m) if the line lx+my=1 touches the circles x...

    Text Solution

    |

  13. A tangent to the circle x^(2)+y^(2)=4 meets the coordinate axes at P a...

    Text Solution

    |

  14. The tangents to x^(2)+y^(2)=a^(2) having inclinations alpha and beta i...

    Text Solution

    |

  15. A line segment AM=a moves in the XOY plane such that AM is parallel to...

    Text Solution

    |

  16. The circle 4x^(2)+4y^(2)-12x-12y+9=0

    Text Solution

    |

  17. If x^(2)+y^(2)-4x-6y+k=0 touches x-axis then k=

    Text Solution

    |

  18. If x^(2)+y^(2)+6x+2ky+25=0 to touch y-axis then k=

    Text Solution

    |

  19. Find the equation of the circle with centre (-3, 4) and touching y-...

    Text Solution

    |

  20. Find the equation of the circle with centre (-3, 4) and touching y-...

    Text Solution

    |