int sin(logx)+cos(logx)dx=...

`int sin(logx)+cos(logx)dx=`

A

`x sin (logx)+c`

B

`x- sin (logx)+c`

C

`x cos (logx)+c`

D

none

Text Solution

Verified by Experts

The correct Answer is:

A

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Knowledge Check

int(logx)/((1+ logx)^(2))dx=

A

`(-x)/(1+log x)+c`

B

`(x)/(1+log x)+c`

C

`(x)/(1-log x)+c`

D

none

int (sin(x-a))/(cos (x-b))dx=

A

`cos(b+a) log |sec (x+b)|+ x sin (b-a)+c`

B

`cos(b-a) log |sec (x-b)|+x sin (b-a)+c`

C

`cos(b-a) log |sec (x-b)|+ xsin (b-a)+c`

D

none

int sin^(3)x cos x dx=

A

`(1)/(2) sin^(4)x+c`

B

`(1)/(4) sin^(4)x+c`

C

`(1)/(3) sin^(4)x+c`

D

none

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