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If I(n) = int (sin nx)/(sin x)dx where n...

If `I_(n) = int (sin nx)/(sin x)dx` where `n gt 1`, then `I_(n)-I_(n-2)`

A

`(2)/(n-1)cos(n-1)x`

B

`(2)/(n-1)sin(n-1)x`

C

`(2)/(3)cos nx`

D

`(2)/(3)sin nx`

Text Solution

Verified by Experts

The correct Answer is:
B
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