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If I(n)=int (cos nx)/(cosx)dx, then I(n)...

If `I_(n)=int (cos nx)/(cosx)dx,` then `I_(n)=`

A

`(2)/(n+1)sin(n-1)x-I_(n-2)`

B

`(2)/(n-1)sin(n+1)x-I_(n-2)`

C

`(2)/(n-1)sin(n-1)x-I_(n-2)`

D

`(3)/(n-1)sin(n+1)x+I_(n-2)`

Text Solution

Verified by Experts

The correct Answer is:
C
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