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int tan^(5) theta d theta=...

`int tan^(5) theta d theta=`

A

`(1)/(4) tan^(4) theta-(1)/(2) tan^(2) theta+ log |sec theta|+c`

B

`(1)/(4) tan^(4) theta+(1)/(2) tan^(2) theta+ log |sec theta|+c`

C

`(1)/(4) tan^(4) theta-(1)/(2) tan^(2) theta- log |sec theta|+c`

D

none

Text Solution

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The correct Answer is:
A
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