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int "cosec"^(6)x dx=...

`int "cosec"^(6)x dx=`

A

`(1)/(5)"cosec"^(4)x cotx-(4)/(15)"cosec"^(2)x cot x-(8)/(15)cot x+c`

B

`-(1)/(5)"cosec"^(4)x cotx-(4)/(15)"cosec"^(2)x cot x-(8)/(15)cot x+c`

C

`(1)/(5)"cosec"^(4)x cotx+(4)/(15)"cosec"^(2)x cot x+ (8)/(15)cot x+c`

D

none

Text Solution

Verified by Experts

The correct Answer is:
B
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