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If (log)k xdot(log)5k=(log)x5,k!=1,k >0,...

If `(log)_k xdot(log)_5k=(log)_x5,k!=1,k >0,` then `x` is equal to
(a) `k` (b) `1/5` (c) 5 (d) none of these

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To solve the equation given in the problem, we start with the equation: \[ (\log_k x) \cdot (\log_5 k) = \log_x 5 \] ### Step 1: Rewrite the logarithms using change of base formula We can use the change of base formula for logarithms, which states that: ...
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