Home
Class 12
MATHS
nd are inclined at avgicsTangents are dr...

nd are inclined at avgicsTangents are drawn from the point `(alpha, beta)` to the hyperbola `3x^2- 2y^2=6` and are inclined atv angle `theta and phi` to the x-axis.If `tan theta.tan phi=2`, prove that `beta^2 = 2alpha^2 - 7`.

Promotional Banner

Topper's Solved these Questions

  • HYPERBOLA

    MOTION|Exercise EXERCISE-4 (Level-I)|4 Videos
  • HYPERBOLA

    MOTION|Exercise EXERCISE-4 (Level-II)|17 Videos
  • HYPERBOLA

    MOTION|Exercise EXERCISE-2 (Level-II)|5 Videos
  • FUNCTION

    MOTION|Exercise Exercise - 4 | Level-II|7 Videos
  • INDEFINITE INTEGRATION

    MOTION|Exercise EXERCISE - 4 (LEVEL - II)|6 Videos

Similar Questions

Explore conceptually related problems

nd are inclined at avgics Tangents are drawn from the point (alpha,beta) to the hyperbola 3x^(2)-2y^(2)=6 and are inclined atv angle theta and phi to the x-axis.If tan theta.tan phi=2 , prove that beta^(2)=2 alpha^(2)-7

Tangents are drawn from the point (alpha,2) to the hyperbola 3x^(2)-2y^(2)=6 and are inclined at angles theta and phi to the x-axis.If tan theta,tan phi=2, then the value of 2 alpha^(2)-7 is

Tangents are drawn from the point ((alpha,beta)) to the hyperbola 3x^(2)-2y^(2)=6 and are inclined at angle theta and phi to the X - axis.If tan theta*tan phi=2 ,then the value of 2 alpha^(2)-beta^(2) is

If two perpendicular tangents can be drawn from the point (alpha,beta) to the hyperbola x^(2)-y^(2)=a^(2) then (alpha,beta) lies on

If 2tan beta+cot beta=tan alpha, prove that cot beta=2tan(alpha-beta)

Tangents drawn from the point (c, d) to the hyperbola (x^(2))/(a^(2))-(y^(2))/(b^(2))=1 make angles alpha and beta with the x-axis. If tan alpha tan beta=1 , then find the value of c^(2)-d^(2) .

If 3tan theta tan phi=1. Prove that 2cos(theta+phi)=cos(theta-phi)

If tan^(2)theta=2tan^(2)phi+1, prove that cos2 theta+sin^(2)phi=0

if 2tan beta+cot beta=tan alpha then prove that cot beta=2tan(alpha-beta)

If tan^(2)theta=1+2tan^(2)phi, prove that cos2 phi=1+2cos2 theta

MOTION-HYPERBOLA-EXERCISE-3
  1. Find the equation of the tagent to the hyperbola x^(2)-4y^(2)=36 which...

    Text Solution

    |

  2. Tangents are drawn to the hyperbola 3x^2-2y^2=25 from the point (0,5/2...

    Text Solution

    |

  3. nd are inclined at avgicsTangents are drawn from the point (alpha, bet...

    Text Solution

    |

  4. Let 'p' be the perpendicular distance from the centre C of the hyperbo...

    Text Solution

    |

  5. The tangent & normal at a point on x^2/a^2-y^2/b^2=1 cut the y-axis re...

    Text Solution

    |

  6. Find the locus of the foot of perpendicular from the centre upon any ...

    Text Solution

    |

  7. If the normal at a pont P to the hyperbola x^2/a^2 - y^2/b^2 =1 meets ...

    Text Solution

    |

  8. The normla to the hyperbola (x^2)/(a^2)-(y^2)/(b^2)=1 drawn at an extr...

    Text Solution

    |

  9. Find the equations of the tangents to the hyperbola x^2=9y^2=9 that ar...

    Text Solution

    |

  10. An ellipse and a hyperbola have their principal axes along the coor...

    Text Solution

    |

  11. An ellipse has eccentricity 1/2 and one focus at the point P(1/2,1)....

    Text Solution

    |

  12. Prove that the part of the tangent at any point of the hyperbola (x^2)...

    Text Solution

    |

  13. Find the length of the diameter of the ellipse x^(2)/(25)+y^(2)/(9)=1 ...

    Text Solution

    |

  14. The tangent at P on the hyperbola x^(2)/a^(2)-y^(2)/b^(2)=1 meets one ...

    Text Solution

    |

  15. From any point of the hyperbola x^(2)/a^(2)-y^(2)/b^(2)=1, tangents a...

    Text Solution

    |

  16. If two points P & Q on the hyperbola ,x^2/a^2-y^2/b^2=1 whose centre i...

    Text Solution

    |

  17. The asymptotes of a hyperbola are parallel to lines 2x+3y=0 and 3x+2y=...

    Text Solution

    |

  18. If a hyperbola passing through the origin has 3x-4y-1=0 and 4x-3y-6=0 ...

    Text Solution

    |

  19. The tangent at any point of a hyperbola 16x^(2) – 25y^(2) = 400 cuts o...

    Text Solution

    |

  20. Text Solution

    |