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In a triangleABC, [tan(A/2) tan(C/2)] is...

In a `triangleABC`, `[tan(A/2) tan(C/2)]` is equal to

A

`(ab)/(R )`

B

`(2ab)/(triangle)`

C

`c cot (C/2)`

D

None of these

Text Solution

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The correct Answer is:
C
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