If AD, BE and CF are the medians of a AB...

If AD, BE and CF are the medians of a ABC ,then `(AD^(2)+BE^(2)+CF^(2)):(BC^(2)+CA^(2)+AB^(2))` is equal to

`4 : 3`

`3 : 2`

`3 : 4`

`2 : 3`

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MOTION-SOLUTION OF TRIANGLE-EXERCISE -1

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