If in triangle A B C ,sumsinA/2=6/5a n d...

If in triangle `A B C ,sumsinA/2=6/5a n dsumI I_1=9` (where `I_1,I_2a n dI_3` are excenters and `I` is incenter, then circumradius `R` is equal to `(15)/8` (b) `(15)/4` (c) `(15)/2` (d) `4/(12)`

`(15)/(8)`

`(15)/(4)`

`(4)/(12)`

`(15)/(2)`

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