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If the median AD of triangle ABC divides...

If the median AD of triangle ABC divides the angle BAC in the ratio `1:2, ` then show that `(sinB)/(sinC)=1/2sec(A/3).`

A

`2 cos (A/3)`

B

`(1)/(2) sec (A)/(3)`

C

`(1)/(2) sin (A)/(3)`

D

`2 cosec (A)/(3)s`

Text Solution

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The correct Answer is:
B
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