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When a tuning fork A of frequency 100 Hz...

When a tuning fork `A` of frequency `100 Hz` is sounded with a tuning fork `B`, the number of beats per second is `2`. On putting some wax on the prongs of `B`, the number of beats per second becomes `1`. The frequency of the fork `B` is

A

101

B

99

C

102

D

98

Text Solution

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The correct Answer is:
C
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MOTION-SOUND WAVES-Exercise - 1
  1. The number of beats produced per second is equal to the –

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  2. Beats are the result of

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  3. When a tuning fork A of frequency 100 Hz is sounded with a tuning fork...

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  4. If two tuning fork A and B are sounded together they produce 4 beats p...

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  5. 56 tuning forks are so arranged in series that each fork gives 4 beats...

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  6. Two waves y=0.25 sin 316 t and y=0.25 sin 310 t are travelling in sa...

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  7. A sources of sound gives 5 beats per second when sounded with another ...

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  8. A sonometer wire is 31 cm long is in resonance with a turning fork of ...

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  9. A set of 24 tuning fork is arranged in a series of increasing frequenc...

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  10. Doppler’s effect will be more effectively observed when the observer -

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  11. Doppler effect is not applicable

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  12. Doppler’s effect can be observed for -

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  13. Doppler’s displacement doesn’t depend upon -

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  14. Apparent frequency of train A is heard by observer in train B as 3/4 o...

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  15. A source and a listener are in unidirection at motion with velocities ...

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  16. Which of the following property of waves is proved by Doppler’s effect...

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  17. A source of frequency n is moving with a uniform velocity v towards a ...

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  18. If an observer is moving with uniform velocity v to wards a stationary...

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  19. A source of sound crosses a stationary observer which is moving with u...

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  20. If a source of frequency n moving with velocity v crosses a stationary...

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