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When the angle of elevation of a gun are...

When the angle of elevation of a gun are `60^(@)` and `30^(@)` respectively, the height it shoots are `h_(1)` and `h_(2)` respectively, `h_(1)//h_(2)` equal to –

A

`3//1`

B

`1//3`

C

`1//2`

D

`2//1`

Text Solution

Verified by Experts

For angle of elevation of `60^(@)` we have maximum height
`h_(1)=(u^(2)sin^(2)60^(@))/(2g)=(3u^(2))/(8g)`
For angle of elevation of `30^(@)`, we have maximum height
`h_(2)=(u^(2)sin^(2)30^(@))/(2g)=(u^(2))/(8g)`
`(h_(1))/(h_(2))=(3)/(1)`
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