If T be the total time of flight and H be the maximum height attained by a stone from the point of projection, then `H//T` will be ( u=projection velocity and `theta`=projection angle )

Options

A. `(1//2)sintheta`
B. `(1//4)u sintheta`
C. `usintheta`
D. 2u sin`theta`

Explanation

To solve the problem, we need to find the ratio \( \frac{H}{T} \) where \( H \) is the maximum height attained by a projectile and \( T \) is the total time of flight.

### Step-by-Step Solution:

1. **Identify the formulas for maximum height (H) and time of flight (T)**:
- The formula for the maximum height \( H \) attained by a projectile is given by:
\[
H = \frac{u^2 \sin^2 \theta}{2g}
...