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A projectile thrown from a height of 10 ...

A projectile thrown from a height of 10 m with velocity of `sqrt(2)m//s` the projectile will fall, from the foot of projection, at distance- `(g=10m//s^(2))`

A

1m

B

2m

C

3m

D

`sqrt2m`

Text Solution

Verified by Experts

The horizontal range of the projectile on the ground
`R = usqrt((2h)/(g ))`
`implies R= sqrt2 sqrt( (2xx10)/10 )= sqrt2 .sqrt2 = 2m`
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