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Out of the following, amphiprotic specie...

Out of the following, amphiprotic species are `I. HPO_(3)^(2-)` II. `OH^(-)` III. `H_(2)PO_(4)^(-)` IV. `HCO_(3)^(-)`

A

I, III, IV

B

I and III

C

III and IV

D

All

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The correct Answer is:
To determine which of the given species are amphiprotic, we need to analyze each species to see if they can both donate and accept protons (H⁺ ions). Amphiprotic species can act as either an acid (donating a proton) or a base (accepting a proton). Let's evaluate each species one by one: ### Step 1: Evaluate HPO₃²⁻ - **Acidic Behavior**: HPO₃²⁻ can potentially donate a proton to form HPO₃³⁻, but it does not have any acidic protons left to donate further. - **Basic Behavior**: It cannot accept a proton to form a stable species. - **Conclusion**: HPO₃²⁻ is **not amphiprotic**. ### Step 2: Evaluate OH⁻ - **Acidic Behavior**: OH⁻ can accept a proton to form H₂O. - **Basic Behavior**: It can theoretically donate a proton to form O²⁻, but O²⁻ is highly unstable. - **Conclusion**: OH⁻ is **not amphiprotic**. ### Step 3: Evaluate H₂PO₄⁻ - **Acidic Behavior**: H₂PO₄⁻ can donate a proton to form HPO₄²⁻. - **Basic Behavior**: It can accept a proton to form H₃PO₄. - **Conclusion**: H₂PO₄⁻ is **amphiprotic**. ### Step 4: Evaluate HCO₃⁻ - **Acidic Behavior**: HCO₃⁻ can donate a proton to form CO₃²⁻. - **Basic Behavior**: It can accept a proton to form H₂CO₃. - **Conclusion**: HCO₃⁻ is **amphiprotic**. ### Final Conclusion The amphiprotic species among the given options are: - **III. H₂PO₄⁻** - **IV. HCO₃⁻** ### Summary of Results - **Amphiprotic Species**: H₂PO₄⁻ and HCO₃⁻ - **Not Amphiprotic**: HPO₃²⁻ and OH⁻
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(i) State the formula and name the conjugate base of each of the following species : (a) H_(3)O^(+) (b) HSO_(4)^(-) (C ) NH_(4)^(+) (d) HF (e ) CH_(3)COOH (f) CH_(3)NH_(3)^(+) (g) H_(3)PO_(4)(h)H_(2)PO_(4)^(-). (ii) State the formula and name the conjugate acid of each of the following species : (a) OH^(-) (b) HPO_(4)^(2-) (C) H_(2)PO_(4)^(-) (d) CH_(3)NH_(2) (e) CO_(3)^(2-) (f) NH_(3)(g) CH_(3)COO^(-) (h) HS^(-)

The equilibrium constant for the given reaction is approximately 10^(-3) HPO_(4)^(2-)(aq) +HCO_(3)^(-) (aq)hArr H_(2)PO_(4)^(-) (aq) +CO_(3)^(2-)(aq) Which is strongest conjugate base in the given reaction?

How many of the following compounds have sp^(3) hybridisation (i) SO_(4)^(2-) (ii) SO_(5)^(2-) (iii) PO_(4)^(3-) (iv) PO_(5)^(3-) (v) I_(3)^(Theta) (iv) CO_(3)^(2-) (vii) CO_(4)^(2-) .

Which of the following is a Bronsted base ? (i) NH_(3) , (ii) CH_(3)NH_(2) (iii) HCO_(3)^(-) , (iv) SO_(4)^(2-)

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MOTION-IONIC EQUILIBRUIM-Exercise -1
  1. The conjugate acid of NH2^- is

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  2. Out of the following, amphiprotic species are I. HPO(3)^(2-) II. OH^(-...

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  3. In the aqueous solution of MgCl2-

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  4. Ostwald’s dilution law gives satisfactory results for -

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  5. For a binary weak electrolyte, the degree of dissociation is proportio...

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  6. Ostwald dilution law of weak electrolyte HA can be given as :

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  7. The value of PkW" at "25^@C is -

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  8. Kw for water at 25^(@)C is equal to 10^(-14). What is its value at 90^...

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  9. Select the correct statement-

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  10. For an acid solution the [OH^(-)] is

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  11. The aqueous solution whose pH =0 is-

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  12. Pure water ionises as 2H2O (?) Leftrightarrow H3O^+ (a)+OH^¯" (aq)...

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  13. The pKw of water at 50^@C is 13.40. An aqueous solution at 50^@C has p...

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  14. For a 100 ml solution of 10–2 M NaOH the ratio pH: pOH would be –

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  15. How many moles of HCl must be removed from 1 litre of aqueous HCl solu...

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  16. 4.0 g of NaOH and 4.9 g of H(2)SO(4) are dissolved in water and volume...

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  17. Nicotinic acid (K(a)=1.4xx10^(-5)) is repersented by the formula HNiC....

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  18. A monoprotic acid in a 0.1 M solution ionizes to 0.001%. Its ionisatio...

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  19. If the concentration of the weak monoprotic acid HA is C mmol L^(-1) ...

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  20. The formula to calculate pKa for acetic acid is

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