Home
Class 12
CHEMISTRY
Nicotinic acid (K(a)=1.4xx10^(-5)) is re...

Nicotinic acid `(K_(a)=1.4xx10^(-5))` is repersented by the formula HNiC. Calculate its per cent dissociation in a solution, which contains `0.10` mole of nicotinic acid per `2.0` litre of solution.

A

0.67

B

0.18

C

0.018

D

0.08

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • IONIC EQUILIBRUIM

    MOTION|Exercise Exercise -2 (Level -1)|37 Videos
  • IONIC EQUILIBRUIM

    MOTION|Exercise Exercise -2 (Level -II)|31 Videos
  • IONIC EQUILIBRUIM

    MOTION|Exercise Exercise -4 (Level -II)|14 Videos
  • HYDROCARBON

    MOTION|Exercise Exercise - 4 (Level-II)|15 Videos
  • ISOMERISM

    MOTION|Exercise Exercise 4|26 Videos

Similar Questions

Explore conceptually related problems

Nicotinic acid (K_a = 1.4 xx 10^(-5)) is represented by the formula HNiC. Calculate its per cent dissociation in a solution which contains 0.10 mol of nicotinic acid per 2.0 L of solution.

Nicotinic acid (K_(a) = 1.4 xx 10^(-5)) si represented by the formula HNiC . Calculate its percent dissociation in a solution which contains 0.10 moles of nictinic acid per 2.0L of solution.

Calculate the hydrogen ion and hydroxyl ion concentrations of solution containing 0.063 g of pure nitrie acid per litre.

Calculate the pH of a solution containing 2.0 g of NaOH per litre of the solution.

What is the percentage dissociation of 0.1 M solution of acetic acid ? (K_(a)=10^(-5))

Calculate the per cent ionisation of 0.20 M solution of hydrocyanic acid, HCN. K_alpha for HCN = 4.9xx10^(-10)

The ionization constant of acetic acid 1.74xx10^(-5) . Calculate the degree of dissociation of acetic acid in its 0.05 M solution. Calculate the concentration of acetate ion in the solution and its pH .

What is the percentage dissociation of 0.1 M Solution of acetic acid? [k_a(CH_3COOH) = 10^( -5)]

MOTION-IONIC EQUILIBRUIM-Exercise -1
  1. How many moles of HCl must be removed from 1 litre of aqueous HCl solu...

    Text Solution

    |

  2. 4.0 g of NaOH and 4.9 g of H(2)SO(4) are dissolved in water and volume...

    Text Solution

    |

  3. Nicotinic acid (K(a)=1.4xx10^(-5)) is repersented by the formula HNiC....

    Text Solution

    |

  4. A monoprotic acid in a 0.1 M solution ionizes to 0.001%. Its ionisatio...

    Text Solution

    |

  5. If the concentration of the weak monoprotic acid HA is C mmol L^(-1) ...

    Text Solution

    |

  6. The formula to calculate pKa for acetic acid is

    Text Solution

    |

  7. K1 and K2 are the first and second dissociation constants of oxalic ac...

    Text Solution

    |

  8. K(a(1)), K(a(2)) and K(a(3)) are the three dissociation constants of H...

    Text Solution

    |

  9. For two weak acids A and B, the ratio of their percent ionization is 4...

    Text Solution

    |

  10. The pH of two equimolar weak acids are 3.0 and 5.0 respectively. Their...

    Text Solution

    |

  11. The dissociation constant of two weak acids are k(a(1)) & k(a(2)) resp...

    Text Solution

    |

  12. Addition of sodium acetate solution to acetic acid causes the followin...

    Text Solution

    |

  13. The pH of two solutions are 5 and 3 respectively. What will be the pH ...

    Text Solution

    |

  14. Which of the following is an acidic salt –

    Text Solution

    |

  15. Select the correct combination –

    Text Solution

    |

  16. Expression Pkh = pKw - pKa - pKb is not applicable to –

    Text Solution

    |

  17. What is the pH of an aqueous solution of ammonium acetate (Ka= Kb =1....

    Text Solution

    |

  18. If pKb gt pKa then the solution of the salt of weak acid and weak base...

    Text Solution

    |

  19. pOH=7-0.5pKa+0.5 pKb is true for aqueous solution containing which pai...

    Text Solution

    |

  20. For a salt of weak acid and weak base [pKa- pKb] would be equal to –

    Text Solution

    |